8=-4.9x^2+12x+1

Solution for 8=-4.9x^2+12x+1 equation:

8=-4.9x^2+12x+1

We move all terms to the left:

8-(-4.9x^2+12x+1)=0

We get rid of parentheses

4.9x^2-12x-1+8=0

We add all the numbers together, and all the variables

4.9x^2-12x+7=0

a = 4.9; b = -12; c = +7;
Δ = b2-4ac
Δ = -122-4·4.9·7
Δ = 6.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{6.8}}{2*4.9}=\frac{12-\sqrt{6.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{6.8}}{2*4.9}=\frac{12+\sqrt{6.8}}{9.8}
$